Solution
(A). We are given a 1 x 1 x 3 solid.
(B). If it is enlarged by a scale factor of 2, The new dimension will be 2 x 2 x 6
(C). Here we will find the surface Area of the New divided by the surface area of the former
The number (n) needed is
![\begin{gathered} n=(2\left(LB+LH+BH\right))/(2\left(lb+lh+bh\right?) \\ n=(LB+LH+BH)/(lb+lh+bh) \\ n=(2\left(2\right)+2\left(6\right)+2\left(6\right))/(1\left(1\right)+1\left(3\right)+1\left(3\right)) \\ n=(4+12+12)/(1+3+3) \\ n=(28)/(7) \\ n=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ewp4xjqtbb592n6lazj1cyesh91nbpjqfz.png)
Therefore, four 1 x 1 x 3 solids would be needed
(D).
Scale factor = 3
![Volume=3^3=27](https://img.qammunity.org/2023/formulas/mathematics/college/i0c7dgpc4ej9fsl066hp837eewmxxdurol.png)
The volume would be 27 times larger