Question

I have an advanced trig equation involving non-right triangles it is a word problem and a pictures included

Answer 1

Let's draw a diagram of the problem:

Where:

a, b, and c, are distances.

We can find a and b as follows:

`\begin{gathered} b=1.75h\cdot195(mi)/(h)=341.25mi \\ a=2.75h\cdot195(mi)/(h)=536.25mi \end{gathered}`

Now, we can use the law of cosines in order to find c:

`\begin{gathered} c=\sqrt[]{a^2+b^2-2ab\cos (B)} \\ c=\sqrt[]{(536.25)^2+(341.25)^2-2(536.25)(341.25)\cos (125)} \\ c\approx784mi \end{gathered}`

Answer:

She is 784mi from ther starting position