What is the area of a sector bounded by a 48 degree arc?

Question

asked Jul 2, 2023 158k views

1 Answer

ManWithBear · Answer 1 · 2023-07-08T16:47:14+0000

Step 1: Write out the given parameters

$r=9\operatorname{cm},\text{ }\theta=48^0$

Step2: Write out the formula

$\begin{gathered} \text{The area of a sector =}(\theta)/(360)*\pi r^2 \\ \end{gathered}$

then Substitute the value into the formular

$\begin{gathered} (48)/(360)*\pi*9^2 \\ (3888)/(360)\pi \\ =(54)/(5)\pi cm^2 \end{gathered}$

Hence the area of the sector is 54/5πcm² or putting π=3.14

We have

$(54)/(5)*3.14=33.912\operatorname{cm}^2$

Therefore the area of the sector is 33.912cm²