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Two angles are complementary. The larger of the two is 30° more than twice the smaller. Find the 2 angles

User WisZhou
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Let's call the measure of the larger angle as x, and the measure of the smaller angle as y.

When two angles are complementary, their sum is equal to 90º, therefore


x+y=90

The larger of the two is 30° more than twice the smaller, writing this as an equation, we have


x=2y+30

If we substitute this expression for x in the first equation, we have


\begin{gathered} (x)+y=90 \\ (2y+30)+y=90 \\ 2y+30+y=90 \\ 3y+30=90 \\ 3y=90-30 \\ 3y=60 \\ y=(60)/(3) \\ y=20 \end{gathered}

Using this y-value on the first expression, we have


\begin{gathered} x+(20)=90 \\ x+20=90 \\ x=90-20 \\ x=70 \end{gathered}

Then, the larger angle is 70º and the smaller angle is 20º.

User Ed Ballot
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