Answer:
Molality of glucose is 7×10⁻¹⁰ mol/Kg
Step-by-step explanation:
you need to do 2 things before use this formula:
1. Transform 6.36 g of glucose into moles
2. Transform 500 mL of water into grams
1. To transform 6.36 g of glucose into moles, we need to know the molar mass of glucose. The molecular formula of glucose is C₆H₁₂O₆
Molar Mass of:
O = 16
H = 1
C = 12
So, to calculate the molar mass of glucose:
(6x12)+(12x1)+(16x6) = 72 + 12 + 96 = 180 g/mol
Now:
6.36 g of glucose --- x moles
180 g of glucose --- 1 mol
x = 6.36/180
x = 0.035 moles
2. First, transform 500 mL into L = 0.5 liters.
To transform 500 mL of water into grams we need to know the density of the water. It is 997 Kg/m³.
liters to m³:
1 liter --- 0.001 m³
0.5 --- x
x = 5×10⁻⁴ m³
997 Kg --- 1 m³
5×10⁻⁴ --- x
x = 5×10⁻⁷ Kg
Now: 0.035 moles/5×10⁻⁷ Kg =
Molality of glucose is 7×10⁻¹⁰ mol/Kg