Question

The length of a rectangle is three times the width. The perimeter is 49 units. Find the length.

Answer 1

153=(34)
49+65= 98
56<65

Answer 2

The Solution:

Given:

Let the width be W.

Length: L= 3W

P=perimeter=49

Required:

Find the length.

The Formula:

`P=2(L+W)`

Substitute:

`49=2(3W+W)`
`\begin{gathered} 49=2(4W) \\ \\ 49=8W \end{gathered}`
`W=(49)/(8)=6.125\text{ units}`

The length is:

`L=3(6.125)=18.375\text{ units}`

Answer:

18.375 units.