Question

Given parallelogram PQRS below, RT = 88. If TP = x+6, solve for x.

Answer 1

The diagonals of a parallelogram bisect each other. Therefore:

`\begin{gathered} RT=TP \\ so\colon \\ 88=x+6 \\ x=88-6 \\ x=82 \end{gathered}`

Answer:

x = 82