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Write in standard form(expanded)f(×)=3/4(×-2)(×+2)

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\begin{gathered} f(x)=(3)/(4)*(x-2)*(x+2) \\ =(3)/(4)*(x^2-2^2) \\ =(3)/(4)*(x^2-4) \\ =(3)/(4)* x^2-4*(3)/(4) \\ f(x)=(3x^2)/(4)-3 \end{gathered}

Thus, the standard form of the given function is,


f(x)=(3x^2)/(4)-3

User Shlomi Hassid
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