9514 1404 393
Answer:
a. yes. term 122
b. yes. term 6
Explanation:
a. The first term is 4 and the difference is 12-4 = 8. If 972 is a term of the sequence, there will be an integer value n such that ...
t(n) = t(1) +d(n -1) . . . . . for t(1) = 4 and d = 8
972 = 4 +8(n -1)
968 = 8(n -1)
121 = n -1
122 = n . . . . . . . . the sequence could be arithmetic, with term 122 = 972.
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b. The first term is 4 and the common ratio is 12/4 = 3. If 972 is a term of the sequence, there will be an integer value n such that ...
t(n) = t(1)·r^(n-1) . . . . . for t(1) = 4 and r = 3
972 = 4·3^(n-1)
243 = 3^(n-1)
3^5 = 3^(n -1) . . . . . write 243 as a power of 3
5 = n -1 . . . . . . . . . . equate exponents
6 = n . . . . . . . . . the sequence could be geometric, with term 6 = 972.