Okay, here we have this:
Considering the provided graph, we are going to calculate amplitude, period and midline, so we obtain the following:
Amplitude: Since the amplitude is equal to half the distance between the maximum and minimum values of the function, then substituting we get:
Amplitude=(4-(-2))/2
Amplitude=6/2
Amplitude=3
Period: Since the period is the length of the smallest interval that contains exactly one copy of the repeating pattern. So we get:
Period=(5pi/4)-0
Period=5pi/4
Midline:
Mid line=Maximum Value-Amplitude
Mid line=4-3
Mid line (y)=1
Finally we obtain that the amplitude is 3, the period 5pi/4 and the mid line y=1.