For Bus A
The equation is,

Equating the above equation wit the general line equation,
y = mx + b, where m is the slope and b is the y intercept., we have,
m = 125/2 = 62.5
The slope of the linear equation represent the speed of the bus. Thus, the speed of bus A is 62.5.
For Bus B,
Let us take two points on the line, (0,0) and (2,50)
The slope can be calculated as,

Thus, the speed of the bus is 25.
Therefore Bus A travels faster.