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Find a point-slope form for the line with slope 5/1 and passing through the point (-6,-7).

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We are asked to find the equation of a line. Let's remember the general form of a line equation:


y=mx+b

Where "m" is the slope and "b" the y-intercept. We are told that the line has a slope of 5, replacing that into the equation we get:


y=5x+b

Now, we are also told that the line passes through the point (-6,-7), which means that when x = -6, y = -7. We can use this to find "b", replacing in the equation, like this:


\begin{gathered} y=5x+b \\ -7=5(-6)+b \end{gathered}

Solving the operations:


-7=-30+b

Now we solve for "b", first by adding 30 on both sides:


\begin{gathered} -7+30=-30+30+b \\ 23=b \end{gathered}

Replacing the value of "b" into the equation of the line:


y=5x+23

And this is the equation of the line

User Brad Culberson
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