Imani picked up 40 bushels of apple in 8.2 hours.
And Chelsea picked up 40 bushels of apple in 10.8 hours
Let I be Imani ratio, hence we have
![I=(40)/(8.2)](https://img.qammunity.org/2023/formulas/mathematics/college/4f9ok2c5i6fbqs9m300qsq0ytw42la7l44.png)
and let C be Chelsea ratio, hence,
![C=(40)/(10.8)](https://img.qammunity.org/2023/formulas/mathematics/college/ytegjl2lqstelvv16a6qobjd6emr6p8wy5.png)
Now, let T be the ratio when Chelsea and Imani work together. In this case, we have
![T=(40)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/q02fv3mbqh113796xj7flwhwby9eej440o.png)
where t is the time for their work.
This means that,
![I+C=T](https://img.qammunity.org/2023/formulas/mathematics/college/c9d7hnydem9k0w0xzcpz50ghuifjhv6iy2.png)
that is, this equality must be fulfilled in order to compare both cases. Hence,
![(40)/(8.2)+(40)/(10.8)=(40)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/4ubwze6cry3tv99kvhnct3pwsaab376b2c.png)
we can factorize 40 in both sides, hence, we have that
![(1)/(8.2)+(1)/(10.8)=(1)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/u0c4zqssquyey4cja95e3bpzu1an6480c5.png)
Now, we must solve this equality for t. Therefore, we have
![(10.8+8.2)/((10.8)(8.2))=(1)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/lz207hdo0y3cmox78egi0no8jf4p4is80o.png)
or
![(19)/(88.56)=(1)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/sfl9an2xc8jq4qvwu584cw2ox3cbr0wx8l.png)
it yields,
![0.2145=(1)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/hzyv11h16uxixzlu52nqk3kgw0ge5hi72n.png)
Finally, t is equal to
![\begin{gathered} t=(1)/(0.2145) \\ t=4.66 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w4gg4kqiag9ng0czh6fwsmy9tui8gf8uxu.png)
that is, of they work together, they will take 4.66 hours only