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Find an equation of the line parallel to −5x+7y=3 that passes through the point (9,−4). If possible, write the equation in slope-intercept form.

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From the original equation we have:


-5x+7y=3
7y=5x+3
y=(5)/(7)x+(3)/(7)

The slope of this line is 5/7 and for the new equation to be parallel to the original must have the same slope, and using the point-slope formula we have:


y-(-4)=(5)/(7)(x-9)
y+4=(5)/(7)x-(45)/(7)
y=(5)/(7)x-(45)/(7)-4
y=(5)/(7)x-(73)/(7)

User Daniele Faugiana
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