Question

How much water isneeded to make a1.5 M solution using44 grams of CaCO3?

Answer 1

The first step we have to follow to answer this question is to convert the given mass to moles using CaCO3 molar mass:

`44gCaCO_3\cdot(1molCaCO_3)/(100.1gCaCO_3)=0.44molCaCO_3`

Now, use the following formula to find the volume of water needed to prepare the solution:

`\begin{gathered} molarity=(molesofsolute)/(litersofsolution) \\ 1.5M=(0.44mol)/(L) \\ L=(0.44mol)/(1.5M) \\ L=0.29L \end{gathered}`

It means that 0.29L are needed.