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How many moles are in a gas sample occupying 0.500L at 170 mmHg and 250C?Group of answer choices0.004570.006002.183.483.85

User Peike
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1 Answer

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Step-by-step explanation:

To solve this kind of problem we usually use the ideal gas law. The formula is:

P * V = n * R * T

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature. R is 0.082 atm*L/(mol*K), so we have to convert the temperature from °C to K and the pressure from mmHg to atm before solving the formula.

R = 0.082 atm*L/(mol*K)

V = 0.500 L

T(K) = T(°C) + 273.15 K

T(K) = 250 + 273.15 K

T(K) = 523.15 K

760 mmHg = 1 atm

P = 170 mmHg * 1 atm/(760 mmHg)

P = 0.224 atm

Now we can replace those values and solve the formula for the number of moles.

P * V = n * R * T

n = P * V/(R*T)

n = 0.224 atm * 0.500 L/(0.082 atm*L/(mol*K) * 523.15 K)

n = 0.00261 mol

Answer: There are 0.00261 mol in the sample.

If the temperature is 25 °C.

T = (273.15 + 25) K

T = 298.15 K

n = 0.224 atm * 0.500 L/(0.082 atm*L/(mol*K) * 298.15 K)

n = 0.00457 mol

Answer: There are 0.00457 mol in the sample.

User Szymon Maszke
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