Explanation:
Assuming a basis of 100 grams
composition of Potassium = 44.2%
composition of potassium = 0.442
mass of potassium = 0.442 x 100g
Mass of potassium= 44.2 grams
mole of potassium = reacting mass / molar mass
Molar mass of potassium = 39.1 gram/ mol
Mole of potassium = 44.2 / 39.1
Mole of potassium = 1.13 moles
mole of potassium chloride + mole of potassium nitrate = mole of potassium
n(KCL) + n(KNO3) = n(k)
since mole (n) = m/M.M
Then we have,
m(KCL)/M.M(KCL) + m(KNO3)/M.M (KNO3) = 1.13
M.M (KCL) = 39.1 + 35.5
M.M (KCL) = 74.6 gram/mol
M.M (KNO3) = 39.1 + 14 + 3(16)
M.M (KNO3) = 39.1 + 14 + 48
M.M (KNO3) = 101.1 gram/mol
Let the mass of KCL be x
Let the mass of KNO3 be y
Assuming the total mass of the mixture is 100g
x + y = 100 ---------- equation 1
x/74.6 + y/101.1 = 1.13 ---- equation 2
From the first equation, make x the subject of the formula
x = 100 - y
100- y / 74.6 + y/101.1 = 1.1.3
1.355(100 - y) + y = 1.13 * 101.1
135.52 - 1.355y + y = 114.243
Collect the like terms
-1.355y - y = 114.243 - 135.52
-0.355y = -21.277
Divide both sides by -0.355
-0.355y/-0.355 = -21.277/-0.355
y = 59.9grams
y is 60 grams approximately
Recall, y is the mass of KNO3
From the first equation
x + y = 100