Question

How do I solve this problem? Directions: Factor each expression completely.

Answer 1

Given:

`2n^2+4n-48`

To factor the given expression, we first factor out the common term 2:

`2n^2+4n-48=2(n^2+2n-24)`

Next, we note that -4 and 6 are the two numbers that add up to 2 and multiply -24. Hence, we rewrite the expression:

`n^2+2n-24=(n-4)(n+6)`

Therefore, the answer is:

`2(n-4)(n+6)`