Question

What is the mass in grams of 5.024x1023 platinum atoms?

Answer 1

1) We have that one mole of Platinum is 195,084 g/mol

2) The Avogadro number is 6,022x1023.

`\text{Grams of Platinum=}\frac{195,084\text{ g}}{1\text{ mol}}\cdot\frac{1\text{ mol}}{6.022\cdot10^(23)}\cdot(5,024\cdot10^(23))/(\square)`