We need to write our reaction:
Ti + 2 F2 ==> TiF4
We have 2 reactants with 2 quantities of each one. To calculate the moles of TiF4 we need to know first which one is the limiting reactant.
We proceed like this:
Moles of Ti = 12.28 moles
Moles of F2 = 3.87 moles
We work with stoichiometry,
1 mol Ti --------- 2 x 1 mole F2
12.28 moles Ti ---------- X = 24.56 moles
According to this result, for 12.28 moles of Ti, we need 24.56 moles of F2, but we only have 3.87. So, The limiting reactant is F2 (we use this to calculate the number of moles of TiF4)
Moles of TiF4)
2 x 1 mole F2 -------------- 1 mole TiF4
3.87 moles F2 -------------- X = 1.94 moles
Answer: 1.94 moles TiF4