Question

The quadrilaterals ABCD and JKLM are similar.Find the length x of JK.DA=5MJ=7AB=7JK=x

Answer 1

Since the quadrilaterals ABCD and JKLM are similar, we get that:

`(MJ)/(DA)=(JK)/(AB)\text{.}`

Substituting DA=5, MJ=7, AB=7, and JK=x we get:

`(7)/(5)=(x)/(7).`

Multiplying the above equation by 7 we get:

`\begin{gathered} (7)/(5)*7=(x)/(7)*7, \\ (49)/(5)=x\text{.} \end{gathered}`

Answer:

`x=9.8.`