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Write the slope-intercept form of the equation that goes through the point (0, 0) and is parallel to the line that has a slope of -6. y=-3x y=-3X-6 y= -6x y=-6x6 now

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To find the equation of a line when having the slope and a point, we use the point-slope equation:


y-y_1=m(x-x_1)

Where m is the slope and (x1,y1) is the point.

In this case, since the point is (0,0):


\begin{gathered} x_1=0 \\ y_1=0 \end{gathered}

And we are told that the line is parallel to a line that has a slope of -6. Something that is important to solve this problem is:

• Parallel line have ,the same slope

So the slope of the line is also -6:


m=-6

Now we are ready to use the point-slope equation:


y-y_1=m(x-x_1)

Substituting m, x1, and y1:


y-0=-6(x-0)

Simplifying the expression, we get the slope-intercept form:


y=-6x

Answer: y=-6x

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