Question

A bag contains 8 red and 4 yellow marbles. Two marbles are chosen at random and notreplaced. What is the probability that 1 marble will be yellow and 1 marble will be red?Answer choices2/3316/331/81/32

Answer 1

Given:

`\begin{gathered} Red,R=8 \\ Yellow,Y=4 \\ Total=12 \end{gathered}`

The probability that 1 marble will be yellow and 1 marble will be red is;

`\begin{gathered} P(YR)\text{ or }P(RY)=((4)/(12)*(8)/(11))+((8)/(12)*(4)/(11)) \\ P(YR)\text{ or }P(RY)=(32)/(132)+(32)/(132) \\ P(YR)\text{ or }P(RY)=(64)/(132) \\ P(YR)\text{ or }P(RY)=(16)/(33) \end{gathered}`

Therefore, the probability that 1 marble will be yellow and 1 marble will be red is