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Find the element that is oxidized and the one that is reduced 2 FeCl3 + SnF2 --> 2 FeF2 + SnCl4

User SandRock
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Step-by-step explanation

2 FeCl3 + SnF2 => 2 FeF2 + SnCl4

The half-reaction: oxidation


\text{ Sn}^(+2)=>\text{ 2e}^(-1)+\text{ Sn}^(+4)

The half-reaction: reduction


2\text{ Fe}^(+3)+\text{ 2e}^(-1)=>\text{ 2Fe}^(+2)

Answer: Sn is oxidized and Fe is reduced

User Ravish Chawla
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