Given:
Total number of animals = 300
Number of rabbits is 10 less than one-half the number of cats
There are 25 more cats than dogs.
Let's find the number of each type of animal.
Let c represent the number of cats.
Let r represent the number of rabbits.
Let d represent the number of dogs.
Number of rabbits is 10 less than one-half the number of cats. This is expressed algebraically as:
r = 0.5c - 10
There are 25 more cats than dogs. This is expressed as:
d = c - 25
Hence, we have the equation:
c + (0.5c - 10) + (c - 25) = 300
Let's solve for c in the equtaion.
Remove the parentheses:
c + 0.5c - 10 + c - 25 = 300
• Combine like terms:
c + c + 0.5c - 10 - 25 = 300
2.5c - 35 = 300
• Add 35 to both sides:
2.5c - 35 + 35 = 300 + 35
2.5c = 335
• Divide both sides by 2.5:
Therefore, there are 134 cats.
• To find the number of rabbits, substitute 134 for c in (0.5c - 10).
Thus, we have:
r = 0.5c - 10
r = 0.5(134) - 10
r = 67 - 10
r = 57
Therefore, the number of rabbits is 57.
To find the number of dogs, substitute 134 for c in (c - 25).
Thus, we have:
d = c - 25
d = 134 - 25
d = 109
Therefore, there are 109 dogs.
ANSWER:
Number of cats, c = 134
Number of dogs, d = 109
Number of rabbits, r = 57