We can use pythagorean theorem to solve for this triangle.
Let , length of other leg of the triangle be "x".
Pythagorean Theorem tells us:

where c is the hypotenuse, a and b are the legs
From the question, we can thus write:

We can solve for x:
![\begin{gathered} 8^2+x^2=17^2 \\ 64+x^2=289 \\ x^2=289-64 \\ x^2=225 \\ x=\sqrt[]{225} \\ x=15 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jxzwm5ymaacyedcfzpbsnwzzwiiyytapoi.png)
So, the other side of the triangle is 15