Question

The force acting on the handle is 40 N at an angle of θ = 35°. How much work is done if the traveler moves 130 meters? Round to the nearest whole number.

Answer 1

Explanation:

Given:

F = 40 N

Θ = 35°

S = 130 m

___________

A - ?

cos Θ = cos 35° ≈ 0.8192

A = F·S·cos θ

A = 40·130·0.8192 ≈ 4 260 N·m

Answer 2

Work can be calculated as follows:

`W=Fd\cos \theta`

where W represents the work, F the force, d the distance, and θ the angle.

In our problem, we are given all this information, except W, which is the parameter that we have to calculate. In our problem:

• F = 40 N

,

• d = 130 m

,

• θ = 35°

Then, replacing these values in the formula:

`W=40\cdot130\cdot\cos (35)`
`W=5200\cdot\cos (35)`
`W\approx4259.59Nm`

Rounding to the nearest whole number:

`W\approx4260Nm`

Answer: 4,260Nm