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In the diagram below, overline BE perp overline ED , overline AC cong overline BC . and m angle A=70^ . Find m angle D .

In the diagram below, overline BE perp overline ED , overline AC cong overline BC-example-1
User Dizarray
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1 Answer

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As segment AC is congruent to segment BC, then we can conclude that ΔACB is an isosceles triangle.

In an isosceles triangle, the base angles (in this case, ∠A and ∠B) have the same measure. Thus:


m\angle A=m\angle B
m\angle B=70

Based on the latter, we can get m∠C knowing that the addition of the interior angles of a triangle add up to 180°:


m\angle A+m\angle B+m\angle C=180
m\angle C=180-m\angle A-m\angle B
m\angle C=180-70-70
m\angle C=40

As ∠C has two opposite angles, then the measure of each is the same. Finally, following the same logic, to get m∠D we have to subtract ∠C and ∠E from 180° as follows:


m\angle E+m\angle D+m\angle C=180
m\angle D=180-m\angle E-m\angle C
m\angle D=180-90-40
m\angle D=50

Answer: 50°

User Slillibri
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