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Larry is double the age of Moe. Moe is 2 years younger than Curly. If you add together the ages of Moe, Curly, and Larry, the total comes to 66. How old are Larry, Moe, and Curly?What are the equations needed to solve this problem?

User Manroe
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1 Answer

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Let L represent the age of Larry

Let M represent the age ofMoe

Let C represent the age of Curly

From the information given,

Larry is double the age of Moe. This means that

L = 2M

Moe is 2 years younger than Curly. This means that

M = C - 2

If you add together the ages of Moe, Curly, and Larry, the total comes to 66. This means that

M + C + L = 66

Thus, the required equations to solve the problem are

L = 2M

M = C - 2

M + C + L = 66

From the second equation, C = M + 2

We would substitute L = 2M and C = M + 2 into M + C + L = 66. We have

M + M + 2 + 2M = 66

4M + 2 = 66

4M = 66 - 2 = 64

Dividing both sides of the equation by 4,

M = 64/4

M = 16

L = 2M = 2 x 16

L = 32

C = M + 2 = 16 + 2

C = 18

Thus,

larry = 32

Moe = 16

Curly = 18

User Ibininja
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