Question

What is the electric field between the plates of a capacitor that has a charge of 10.75 microC and voltage difference between the plates of 97.87 Volts if the plates are separated by 2.11 mm?

Answer 1

The eletric field on a capacitor is given by the following formula:

`E=(Q)/(A\epsilon_0)=(V)/(d)`

Where Q is the difference of charge between plates, A is the area, and e0 is a constant. It can also be written as the second formula, where V is the voltage, and d is the distance between plates.

When we use the second formula, with the values from the exercise, we get:

`E=(97.87)/(2.11*10^(-3))=46383.886[(V)/(m)]`

Thus, our final answer is E=46383.886 V/m