Question

Instructions: Solve the system. Enter your answer as an ordered pair.

Answer 1

Given the system:

`\begin{gathered} 3x-9y=12\text{ Eq. 1} \\ 3x+4y=-1\text{ Eq. 2} \end{gathered}`

First, we solve for 3x on both equations, as follows:

`\begin{gathered} 3x=12+9y \\ 3x=-1-4y \end{gathered}`

Equating both equations:

`\begin{gathered} 12+9y=-1-4y \\ 13=-4-9y \\ 13=-13y \\ y=-1 \end{gathered}`

Substituting y on equation 2:

`\begin{gathered} 3x+4y=-1\text{ Eq. 2.} \\ 3x+4*(-1)=-1 \\ 3x=-1+4 \\ 3x=3 \\ x=1 \end{gathered}`

ANSWER

(1, -1)