Question

Find 5 consecutive odd integers who's sum is -45(solve algebraically)

Answer 1

let the consecutive odd integers be

x, x+ 1, x+ 2, x + 3, x + 4

Average = sum / total number

Average = -45

Total number = 5

-45 = x + x + 1 + x + 2 + x + 3 + x + 4 / 5

Introduce cross multiplication

-45 x 5 = x + x + 1 + x + 2 + x + 3 + x + 4

-225 = x + x + x + x + x + 1 + 3 + 4 + 5

-225 = 5x + 16