Are the proof and the identity valid? if not, what is the invalid step in the proof
Step 1: x (9x+3) +3(x+3)=9x²+6x+9
Step 2: =(3x+3)²
Step 3: =(3(x+1))²
Step 4: =9(x+1)²
A) the proof is valid
B) step 2 is not valid
C) step 1 is not valid
D) step 3 is not valid
Verify each step
step 1
x (9x+3) +3(x+3)
=9x^2+3x+3x+9
=9x^2+6x+9
step 1 is correct
step 2
Complete squares
9x^2+6x+9=0
Factor 9
9(x^2+6/9x)+9=0
9(x^2+2/3x)+9=0
9(x^2+2/3x+4/36-4/36)+9=0
9(x^2+2/3x+4/36)+9-1=0
9(x^2+2/3x+4/36)+8=0
9(x+2/6)^2=-8
therefore
step 2 is not valid