Question

Calculate the number of grams of glucose (C6H12O6) that would need to be dissolved to a total volume of 1.5L to get a 15.3% (w/v) solution

Answer 1

The mass of glucose in grams is 230 grams

Step-by-step explanation

Given information

The total volume of the solution = 1.5L

Follow the steps below to find the mass of glucose

Step 1: Convert the volume of the solution from L to mL

According to the standard conversion, 1L is equivalent to 1000mL

Let x represents the volume of the solution in mL

`\begin{gathered} \text{ 1L }\rightarrow\text{ 1000mL} \\ \text{ 1.5L }\rightarrow\text{ xmL} \\ \text{ Cross multiply} \\ \text{ 1L }*\text{ xmL = 1000mL }*\text{ 1.5L} \\ \text{ Isolate x} \\ \text{ xmL = }\frac{1000mL*\text{ 1.5L}}{1L} \\ \text{ x = }\frac{1000*1.5\cancel{L}}{1\cancel{L}} \\ \text{ x = 1500mL} \end{gathered}`

Hence, the volume of the solution in mL is 1500mL

Step 2: Find the mass of the glucose in grams

`\begin{gathered} \text{ The mass of glucose = }(15.3)/(100)*\text{ 1500} \\ \text{ The mass of glucose = 0.153 }*\text{ 1500} \\ \text{ The mass of glucose = 229.5 grams} \end{gathered}`

Hence, the mass of glucose in grams is 229.5 grams