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I need help with my homework PLEASE CHECK WORKnumber 4

I need help with my homework PLEASE CHECK WORKnumber 4-example-1

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ANSWER:

Option c


h=-\frac{\operatorname{\ln}(0.62)}{0.079}

Explanation:

The function given in the statement is the following:


D(h)=615\cdot\:e^(-0.079h)

If D(h) = 383, we substitute and solve for h, just like this:


\begin{gathered} 383=615\cdot \:e^(-0.079h) \\ \\ e^(-0.079h)=(383)/(615) \\ \\ \ln(e^(-0.079h))=\ln\left((383)/(615)\right) \\ \\ -0.079h=\ln(0.62) \\ \\ h=-(\ln(0.62))/(0.079) \end{gathered}

Therefore, the correct answer is option c.

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