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2. The admission fee at a small fair is $2.50 for children and $4.00 for adults. On a certain day, 2400 people enter the fair and $7140 is collected. How many children and how many adults attended?

User Vectorizer
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1 Answer

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Given:

a.) The admission fee at a small fair is $2.50 for children and $4.00 for adults.

b.) On a certain day, 2400 people enter the fair and $7140 is collected.

Let,

x = total number of children

y = total number of adults

Let's generate two equations based on the given scenario:

EQUATION 1: Total number of children and adults entered the fair.


\text{ x + y = }2400

EQUATION 2: Total money collected from the admission.


\text{ 2.5x + 4y = }$7140$

We will be using the substitution method. We get,


\text{ x + y = }2400
\text{ y = }2400\text{ - x}

Substitute to Equation 2:


\text{ 2.5x + 4y = }$7140$
\text{ 2.5x + 4(}2400\text{ - x) = }$7140$
\text{ 2.5x + 9600 - 4x = }$7140$
\text{ 2.5x - 4x = }$7140$\text{ - 9600 }
\text{ -1.5x }=\text{ }-2,460
\text{ }\frac{\text{-1.5x}}{-1.5}\text{ }=\text{ }(-2,460)/(-1.5)
\text{ x }=\text{ }1,640\text{ children}

Therefore, 1,640 children went to the fair.

For the adults,

x + y = 2400

1,640 + y = 2400

y = 2400 - 1,640

y = 760 adults

In summary: 1,640 children and 760 adults went to the fair.

User Danka
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