Question

We an equivalent agression for 40+8(n-3)

Answer 1

8n+16

Explanation:

Given the expressions:

`40+8\left(n-3\right)`

First, distribute 8 over the terms in the bracket:

`\begin{gathered} =40+8(n)+8(-3) \\ =40+8n-24 \end{gathered}`

Finally, collect like terms and simplify:

`\begin{gathered} =40-24+8n \\ =16+8n \end{gathered}`

An equivalent expression is 8n+16.