Question

Solve the triangle. round to the nearest tenth A B 16 14 С

Answer 1

`\text{Answer : }\theta\text{ = 41. 2 degr}ees`

According the question

Side AC of the triangle = 16

Side BC = 14

The opposite side of the triangle is AC = 14

The adjacent side of the triangle is BC = 16

Using SOH CAH TOA

`\begin{gathered} \text{Tan }\theta\text{ = }\frac{opposite}{\text{adjacent}} \\ \text{Tan }\theta\text{ = }(14)/(16) \\ \text{Tan }\theta\text{ = 0.875} \\ \theta\text{ = arc tan of 0.875} \\ \theta=tan^(-1)(0.875) \\ \theta\text{ = 41. 18 degre}es \\ To\text{ the nearest tenth} \\ \theta\text{ = 41.2 degre}es \end{gathered}`