Question

Write an equation of the line with the given slope that contains the given point.a) F(3,-6), slope 1/3b) Q(5,2), slope -2c) R(15,10), slope 4/5d) D(1,-9), slope 4

Answer 1

The equation, given slope and 1 point, of a line is given as:

`y-y_1=m(x-x_1)_{}`

Where

m is the slope (Given, 1/3 rd)

(x_1, y_1) is the point (Given, F(3,-6)

Now, let's substitute the given information into the equation:

`\begin{gathered} y-y_1=m(x-x_1) \\ y-(-6)=(1)/(3)(x-3) \end{gathered}`

Now, we simplify and put the answer in the form y = mx + b. Shown below:

`\begin{gathered} y-(-6)=(1)/(3)(x-3) \\ y+6=(1)/(3)x-1 \\ y=(1)/(3)x-1-6 \\ y=(1)/(3)x-7 \end{gathered}`

Answer:

`y=(1)/(3)x-7`