Question

Sean and Darryl are racing on a track. Sean runs 6 miles per hour and gets a 0.25 mile head start. Darryl runs 0.7 mile per hour faster than Sean. If Darryl and Sean run the same distance, how many hours, x, do they run? 6x + 0.25 = 0.7x 0 6x - 0.25 = 3.7x 0 6x +0.25 = 6.7x D 6x + 0.25 = 4.7x

Answer 1

The relation between speed, distance and time is express as :

`\text{ Sp}eed\text{ =}(Dis\tan ce)/(Time)`

Sean and Darryl are racing on a track.

Sean runs 6 miles per hour and gets a 0.25 mile head start.

Speed of Sean = 6

x is the time taken by Sean

So, Distance = speed x Time

Distance travel by sean = 6x

Since, Sean gets a 0.25 mile head start.

So, total distance travel = 6x + 0.25

Darryl runs 0.7 mile per hour faster than Sean,

Speed of darryl = 0.7 + Speed of sean

Speed of daryl = 0.7 + 6

Speed of darryl = 6.7 miles per hour

x is the time taken by Darryl

So, Distance = Speed x Time

Distance = 6.7x

Distance travel by Darryl = 6.7x

Since distance travel by darryl and sean is equal so,

6x + 0.25 = 6.7x

Answer : C) 6x + 0.25 = 6.7x