Question

Yoda uses the Force to make a vertical jump in the air. A Jedi Trainee walks 15 meters from Yoda and looks up. The angle from the ground to the top of Yoda's jump was 58o. How high did Yoda jump in the air?

Answer 1

24 m

Step-by-step explanation:

We can model the situation with the following figure:

So, it can be represented as a right triangle and we want to know the value of h.

Then, we can relate the side of 15 m, h, and the angle of 58° with the trigonometric function tangent, so:

`\begin{gathered} \tan 58=\frac{\text{Opposite side}}{Adjacent\text{ side}} \\ \tan 58=(h)/(15) \end{gathered}`

Because h is the opposite side of 58° and 15 m is the adjacent side of the angle.

So, solving for h, we get:

`\begin{gathered} 15*\tan 58=15*(h)/(15) \\ 15*\tan 58=h \\ 15*1.6=h \\ 24m=h \end{gathered}`

Therefore, Yoda jump 24 m.