Question

A jogger jogs from one end to the other of a straight track in 1.03 min and then back to the starting point in 1.69 min. What is the jogger's average speed at the following points? (Assume the track is 100 m long.)(a) in jogging to the far end of the track m/s(b) coming back to the starting point m/s(c) for the total jog m/s

Answer 1

From the information given,

time taken to jog from one end to the other of a straight track is 1.03 min. We would convert the time to seconds by multiplying by 60. Thus,

time taken to jog from one end to the other = 1.03 x 60 = 61.8s

time taken to jog back = 1.69 min = 1.69 x 60 = 101.4s

distance = 100 m

Distance = speed x time

a) distance = 100

time = 61.8s

average jogger'speed = 100/61.8

average jogger'speed = 1.62 m/s

b) distance = 100

time = 101.4

averge speed = 100/101.4

Average speed when coming back to the starting point = 0.99 m/s

c) Total distance = 100 + 100 = 200

Total time = 61.8 + 101.4 = 163.2

Average speed = 200/163.2

Average speed = 1.23 m/s

Average speed =