How do you graph Y=x^2+4x-4

Question

asked Oct 26, 2023 174k views

1 Answer

Carl Sednaoui · Answer 1 · 2023-10-30T20:07:51+0000

Graph the following function:

We can give x a set of values and calculate the corresponding values for y.

x = -5

$\begin{gathered} y=(-5)^2+4(-5)-4 \\ \\ y=25-20-4=1 \end{gathered}$

The first point is (-5, 1)

x = -4

$\begin{gathered} y=(-4)^2+4(-4)-4 \\ \\ y=16-16-4=-4 \end{gathered}$

The point is (-4, -4)

x = -3

$\begin{gathered} y=(-3)^2+4(-3)-4 \\ \\ y=9-12-4=-7 \end{gathered}$

Point (-3, -7)

x = -2

$\begin{gathered} y=(-2)^2+4(-2)-4 \\ \\ y=4-8-4=-8 \end{gathered}$

Point (-2, -8)

x = -1

$\begin{gathered} y=(-1)^2+4(-1)-4 \\ \\ y=1-4-4=-7 \end{gathered}$

Point (-1, -7)

x = 0

$\begin{gathered} y=(0)^2+4(0)-4 \\ \\ y=0-0-4=-4 \end{gathered}$

Point (0, -4)

Finaly, use x = 1:

$\begin{gathered} y=(1)^2+4(1)-4 \\ \\ y=1+4-4=1 \end{gathered}$

Point (1, 1)

Plotting the points and drawing the graph: