Question

How do you graph Y=x^2+4x-4

Answer 1

Graph the following function:

`y=x^2+4x-4`

We can give x a set of values and calculate the corresponding values for y.

x = -5

`\begin{gathered} y=(-5)^2+4(-5)-4 \\ \\ y=25-20-4=1 \end{gathered}`

The first point is (-5, 1)

x = -4

`\begin{gathered} y=(-4)^2+4(-4)-4 \\ \\ y=16-16-4=-4 \end{gathered}`

The point is (-4, -4)

x = -3

`\begin{gathered} y=(-3)^2+4(-3)-4 \\ \\ y=9-12-4=-7 \end{gathered}`

Point (-3, -7)

x = -2

`\begin{gathered} y=(-2)^2+4(-2)-4 \\ \\ y=4-8-4=-8 \end{gathered}`

Point (-2, -8)

x = -1

`\begin{gathered} y=(-1)^2+4(-1)-4 \\ \\ y=1-4-4=-7 \end{gathered}`

Point (-1, -7)

x = 0

`\begin{gathered} y=(0)^2+4(0)-4 \\ \\ y=0-0-4=-4 \end{gathered}`

Point (0, -4)

Finaly, use x = 1:

`\begin{gathered} y=(1)^2+4(1)-4 \\ \\ y=1+4-4=1 \end{gathered}`

Point (1, 1)

Plotting the points and drawing the graph: