Question

The Haber process for producing ammonia commercially is represented by the equation N2(g) + 3H2(g) → 2NH3(g). To completely convert 9.0 mol H2 gas to NH3 gas, how many moles of nitrogen gas are required?

Answer 1

3 mol N2

Step-by-step explanation

Given:

Moles of H2 = 9.0 mol

Equation: N2(g) + 3H2(g) → 2NH3(g).

What to find:

The moles of nitrogen gas required to completely convert 9.0 mol H2 gas to NH3 gas.

Solution:

From the Balanced equation of reaction given;

3 mol H2 completely reacts with 1 mol N2

∴ 9.0 mol H2 will require

`\frac{9.0\text{ }mol\text{ }H_2}{3.0\text{ }mol\text{ }H_2}*1\text{ }mol\text{ }N_2=3\text{ }mol\text{ }N_2`

Hence, the moles of nitrogen gas required to completely convert 9.0 mol H2 gas to NH3 gas is 3 mol N2.