ANSWER:
750 Hz and 692.3 Hz
Explanation:
Given:
f0 = 720 Hz
vs = 14 m/s
vr = 0 m/s
v = 350 m/s
The corresponding formula for the Doppler effect is as follows:
![f_s=f_o\left((v\pm\:v_o)/(v\pm\:v_s)\right)](https://img.qammunity.org/2023/formulas/physics/college/arfwdpw3ty0uzo1483im1tinb6qn7vt0hi.png)
The first scenario the police car is approaching the cafe, therefore:
![\begin{gathered} f_s=720\cdot\left((350+0)/(350-14)\right) \\ \\ f_s=750\text{ Hz} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/we139jro8i6lb6tex53qt35jclln673jug.png)
The second scenario the police car is moving away from the cafe, therefore:
![\begin{gathered} f_s=720\cdot\left((350+0)/(350+14)\right) \\ \\ f_s=\:692.3\text{ Hz} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/pcc69ysp05snnluity7v8k11gpfey5ylw6.png)
Therefore, the frequency that will be heard when approaching is 750 Hz and when passing the frequency would be 692.3 Hz.