Question

For the following dilution: how many mL of 12.0M HCI stock solution do you need to use to make 2.5L of a 1.75M HCI solution? Hint: Don'tforget to convert liters to mL for your final answer.

Answer 1

364.58 mL

Step-by-step explanation

Given:

Molarity of the stock solution, C₁ = 12.0 M

Molarity of the HCl solution, C₂ = 1.75 M

Volume of the HCl solution, V₂ = 2.5 L

What to find:

The volume of the stock solution, V₁ needed to make 2.5L of a 1.75M HCI solution.

Solution:

The volume of the stock solution V₁ needed to make 2.5L of a 1.75M HCI solution can be calculated using the dilution formula.

`\begin{gathered} C_1V_1=C_2V_2 \\ \\ V_1=(C_2V_2)/(C_1) \\ \\ V_1=(1.75M*2.5L)/(12.0M)=(4.375L)/(12.0)=0.36458\text{ }L \\ \\ Converting\text{ }L\text{ }to\text{ }mL, \\ \\ V_1=0.036458*1000\text{ }mL \\ \\ V_1=364.58\text{ }mL \end{gathered}`

The volume of the stock solution, V₁ needed to make 2.5L of a 1.75M HCI solution is 364.58 mL