Question

“solve the following equations using substitution please show all your work”pleas help i don’t understand how to solve

Answer 1

Step-by-step explanation

We are given the following:

`\begin{gathered} 4x-3y=10\text{ \lparen equation 1\rparen} \\ 4x-2y=3\text{ \lparen equation 2\rparen} \end{gathered}`

We are required to solve the simultaneous equation given using substitution method.

This can be achieved as follows:

`\begin{gathered} \text{ From equation 1, } \\ 4x-3y=10 \\ 4x=10+3y\text{ \lparen equation 3\rparen} \\ \\ \text{ Substitute for ''4x'' in equation 2.} \\ 4x-2y=3 \\ (10+3y)-2y=3 \\ 10+3y-2y=3 \\ 3y-2y=3-10 \\ y=-7 \end{gathered}`

Now, we get the value of x as follows:

`\begin{gathered} \text{ From equation 3} \\ 4x=10+3y \\ where \\ y=-7 \\ 4x=10+3(-7) \\ 4x=10-21 \\ 4x=-11 \\ x=(-11)/(4) \end{gathered}`

Hence, the answer is:

`x=(-11)/(4);y=-7`