Question

How would I do number 2 the concept is confusing

Answer 1

Problem #2:

Given 45-45-90 triangle

The triangle is an isosceles right triangle

so, the legs are congruent ⇒ a = b

Using the Pythagorean theorem

`a^2+b^2=(\text{hypotenuse)}^2`

as shown, hypotenuse = 7√2

so,

`\begin{gathered} a^2+b^2=(7\sqrt[]{2})^2 \\ a^2+b^2=98\rightarrow(a=b) \\ a^2+a^2=98 \\ 2a^2=98 \\ a^2=(98)/(2)=49 \\ a=\sqrt[]{49}=7 \end{gathered}`

so, the answer will be:

`\begin{gathered} a=7 \\ b=7 \end{gathered}`

Another method:

The length of the side opposite to the angle 45 = hypotenuse/√2

So,