Question

cylindrical water container A is 1.2 meters high and diameter 4.6 meters. cylindrical container B is 8 meters in diameter and height 12 meters. what is the difference in the amount of water cylindrical A and cylindrical B will contain to the nearest hundredth?

Answer 1

Given:

Here two cylindrical containers are given with named A and B and the measures are 1.2 m height 4.6 m diameter and 12 meter height and 8 m in diameter respectively.

Required:

We need to find that what is the difference in the amount of water cylindrical A and cylindrical B will contain to the nearest hundredth.

Step-by-step explanation:

Lets consider measures A as 1 and measures B as 2 means

measures of cylinder A is

`\begin{gathered} r_1=(4.6)/(2)=2.3\text{ m} \\ h_1=1.2\text{ m} \\ \end{gathered}`

measure of cylinder A is

`\begin{gathered} r_2=(8)/(2)=4\text{ m} \\ h_2=12\text{ m} \end{gathered}`

now find the volume of named A contained

`V_A=\pi r_1^2h_1=3.14*2.3*2.3*1.2=19.94\text{ m}^3`

now for B

`V_B=\pi r_2^2h_2=3.14*4*4*12=603.19\text{ m}^3`

now to find the difference

`V_B-V_A=603.19-19.94=583.25\text{ m}^3`

Final answer:

Difference of both container is 583.25 cubic meter