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Jenna weighed 250 pounds in August but weighed 280 pounds by December. What is the percent increase in her weight? ANS. _________. %

User NikhilP
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As Jenna weighed 250 pounds in August, this will represent 100%


\begin{gathered} 250lb\rightarrow100percent \\ 280lb\rightarrow xpercent \end{gathered}

This relation leads to the next equation


\begin{gathered} x_{\text{percent}}=\frac{280lb\cdot100_{\text{percent}}}{250lb} \\ \Rightarrow x_{\text{percent}}=\frac{28000_{\text{percent}}}{250} \\ \Rightarrow x_{\text{percent}}=112_{\text{percent}} \end{gathered}

Therefore, the increment in weight is given by


x_{\text{percent}}-100=12_{\text{percent}}

So, the percent increase is 12%

A way of making sure our answer is correct is by doing the next operation


250(1+0.12)=250(1.12)=280

User Justin Pollard
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